Expert Mathematics Quadratic Equations Class 10 Level 29

समीकरण ((x+5)2+(x-6)2=(x+2)2) का मानक रूप कौन-सा है?

What is the standard form of ((x+5)2+(x-6)2=(x+2)2)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-10x+57=0\)

Step 1

Concept

Expanding gives left side \(2x^2-2x+61\) and right side \(x^2+4x+4\). Subtracting gives \(x^2-6x+57=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-10x+57=0\). Expanding gives left side \(2x^2-2x+61\) and right side \(x^2+4x+4\). Subtracting gives \(x^2-6x+57=0\).

Step 3

Exam Tip

विस्तार करने पर बाईं ओर \(2x^2-2x+61\) और दाईं ओर \(x^2+4x+4\) है। घटाने पर \(x^2-6x+57=0\) नहीं बल्कि \(x^2-6x+57=0\) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

समीकरण ((x+5)2+(x-6)2=(x+2)2) का मानक रूप कौन-सा है? / What is the standard form of ((x+5)2+(x-6)2=(x+2)2)?

Correct Answer: A. \(x^2-10x+57=0\). Explanation: विस्तार करने पर बाईं ओर \(2x^2-2x+61\) और दाईं ओर \(x^2+4x+4\) है। घटाने पर \(x^2-6x+57=0\) नहीं बल्कि \(x^2-6x+57=0\) मिलता है। / Expanding gives left side \(2x^2-2x+61\) and right side \(x^2+4x+4\). Subtracting gives \(x^2-6x+57=0\).

Which concept should I revise for this Mathematics MCQ?

Expanding gives left side \(2x^2-2x+61\) and right side \(x^2+4x+4\). Subtracting gives \(x^2-6x+57=0\).

What exam hint can help solve this Mathematics question?

विस्तार करने पर बाईं ओर \(2x^2-2x+61\) और दाईं ओर \(x^2+4x+4\) है। घटाने पर \(x^2-6x+57=0\) नहीं बल्कि \(x^2-6x+57=0\) मिलता है।

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