समीकरण ((x-5)2=16) का मानक रूप कौन-सा है?
What is the standard form of ((x-5)2=16)?
Explanation opens after your attempt
Correct Answer
A. \(x^2-10x+9=0\)
Concept
((x-5)2=x-2-10x+25), so \(x^2-10x+25-16=0\). Do not forget the middle term while using square identities.
Why this answer is correct
The correct answer is A. \(x^2-10x+9=0\). ((x-5)2=x-2-10x+25), so \(x^2-10x+25-16=0\). Do not forget the middle term while using square identities.
Exam Tip
((x-5)2=x-2-10x+25), इसलिए \(x^2-10x+25-16=0\) मिलता है। वर्ग सूत्र लगाते समय मध्य पद न भूलें।
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