Expert Mathematics Quadratic Equations Class 10 Level 28

समीकरण ((x+3)(x+6)+(x-2)(x+5)=70) का मानक रूप कौन-सा है?

What is the standard form of ((x+3)(x+6)+(x-2)(x+5)=70)?

Explanation opens after your attempt
Correct Answer

A. \(2x^2+12x-62=0\)

Step 1

Concept

The left side is \(x^2+9x+18+x^2+3x-10=2x^2+12x+8\). Subtracting (70) gives \(2x^2+12x-62=0\).

Step 2

Why this answer is correct

The correct answer is A. \(2x^2+12x-62=0\). The left side is \(x^2+9x+18+x^2+3x-10=2x^2+12x+8\). Subtracting (70) gives \(2x^2+12x-62=0\).

Step 3

Exam Tip

बाईं ओर \(x^2+9x+18+x^2+3x-10=2x^2+12x+8\) है। (70) घटाने पर \(2x^2+12x-62=0\) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

समीकरण ((x+3)(x+6)+(x-2)(x+5)=70) का मानक रूप कौन-सा है? / What is the standard form of ((x+3)(x+6)+(x-2)(x+5)=70)?

Correct Answer: A. \(2x^2+12x-62=0\). Explanation: बाईं ओर \(x^2+9x+18+x^2+3x-10=2x^2+12x+8\) है। (70) घटाने पर \(2x^2+12x-62=0\) मिलता है। / The left side is \(x^2+9x+18+x^2+3x-10=2x^2+12x+8\). Subtracting (70) gives \(2x^2+12x-62=0\).

Which concept should I revise for this Mathematics MCQ?

The left side is \(x^2+9x+18+x^2+3x-10=2x^2+12x+8\). Subtracting (70) gives \(2x^2+12x-62=0\).

What exam hint can help solve this Mathematics question?

बाईं ओर \(x^2+9x+18+x^2+3x-10=2x^2+12x+8\) है। (70) घटाने पर \(2x^2+12x-62=0\) मिलता है।

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