Hard Mathematics Quadratic Equations Class 10 Level 30

समीकरण ((x+2)(x+5)+(x-1)(x+4)=60) का मानक रूप कौन-सा है?

What is the standard form of ((x+2)(x+5)+(x-1)(x+4)=60)?

Explanation opens after your attempt
Correct Answer

A. \(2x^2+10x-54=0\)

Step 1

Concept

The left side is \(x^2+7x+10+x^2+3x-4=2x^2+10x+6\). Subtracting (60) gives \(2x^2+10x-54=0\).

Step 2

Why this answer is correct

The correct answer is A. \(2x^2+10x-54=0\). The left side is \(x^2+7x+10+x^2+3x-4=2x^2+10x+6\). Subtracting (60) gives \(2x^2+10x-54=0\).

Step 3

Exam Tip

बाईं ओर \(x^2+7x+10+x^2+3x-4=2x^2+10x+6\) है। (60) घटाने पर \(2x^2+10x-54=0\) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

समीकरण ((x+2)(x+5)+(x-1)(x+4)=60) का मानक रूप कौन-सा है? / What is the standard form of ((x+2)(x+5)+(x-1)(x+4)=60)?

Correct Answer: A. \(2x^2+10x-54=0\). Explanation: बाईं ओर \(x^2+7x+10+x^2+3x-4=2x^2+10x+6\) है। (60) घटाने पर \(2x^2+10x-54=0\) मिलता है। / The left side is \(x^2+7x+10+x^2+3x-4=2x^2+10x+6\). Subtracting (60) gives \(2x^2+10x-54=0\).

Which concept should I revise for this Mathematics MCQ?

The left side is \(x^2+7x+10+x^2+3x-4=2x^2+10x+6\). Subtracting (60) gives \(2x^2+10x-54=0\).

What exam hint can help solve this Mathematics question?

बाईं ओर \(x^2+7x+10+x^2+3x-4=2x^2+10x+6\) है। (60) घटाने पर \(2x^2+10x-54=0\) मिलता है।

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