समीकरण ((x-1)2+(x-2)2=(x-3)2) का मानक रूप कौन-सा है?
What is the standard form of ((x-1)2+(x-2)2=(x-3)2)?
Explanation opens after your attempt
Correct Answer
B. \(x^2-2x-4=0\)
Concept
Expanding gives left side \(2x^2-6x+5\) and right side \(x^2-6x+9\). Subtracting gives \(x^2-4=0\).
Why this answer is correct
The correct answer is B. \(x^2-2x-4=0\). Expanding gives left side \(2x^2-6x+5\) and right side \(x^2-6x+9\). Subtracting gives \(x^2-4=0\).
Exam Tip
विस्तार करने पर बाईं ओर \(2x^2-6x+5\) और दाईं ओर \(x^2-6x+9\) है। घटाने पर \(x^2-4=0\) नहीं बल्कि \(x^2-4=0\) मिलता है।
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