What is the reference angle of \(\frac{41\pi}{7}\)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{\pi}{7}\)
Step 1
Concept
The principal angle of \(\frac{41\pi}{7}\) is \(\frac{13\pi}{7}\), which lies in the fourth quadrant. The reference angle is \(2\pi-\frac{13\pi}{7}=\frac{\pi}{7}\).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{\pi}{7}\). The principal angle of \(\frac{41\pi}{7}\) is \(\frac{13\pi}{7}\), which lies in the fourth quadrant. The reference angle is \(2\pi-\frac{13\pi}{7}=\frac{\pi}{7}\).
Step 3
Exam Tip
\(\frac{41\pi}{7}\) का मुख्य कोण \(\frac{13\pi}{7}\) है और वह चौथे चतुर्थांश में है। संदर्भ कोण \(2\pi-\frac{13\pi}{7}=\frac{\pi}{7}\) है।
Mathematics Answer, Explanation and Revision Hints
कोण \(\frac{41\pi}{7}\) का संदर्भ कोण क्या है? / What is the reference angle of \(\frac{41\pi}{7}\)?
Correct Answer: A. \(\frac{\pi}{7}\). Explanation: \(\frac{41\pi}{7}\) का मुख्य कोण \(\frac{13\pi}{7}\) है और वह चौथे चतुर्थांश में है। संदर्भ कोण \(2\pi-\frac{13\pi}{7}=\frac{\pi}{7}\) है। / The principal angle of \(\frac{41\pi}{7}\) is \(\frac{13\pi}{7}\), which lies in the fourth quadrant. The reference angle is \(2\pi-\frac{13\pi}{7}=\frac{\pi}{7}\).
Which concept should I revise for this Mathematics MCQ?
The principal angle of \(\frac{41\pi}{7}\) is \(\frac{13\pi}{7}\), which lies in the fourth quadrant. The reference angle is \(2\pi-\frac{13\pi}{7}=\frac{\pi}{7}\).
What exam hint can help solve this Mathematics question?
\(\frac{41\pi}{7}\) का मुख्य कोण \(\frac{13\pi}{7}\) है और वह चौथे चतुर्थांश में है। संदर्भ कोण \(2\pi-\frac{13\pi}{7}=\frac{\pi}{7}\) है।
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