समीकरण \(9x^2-24x+16=0\) के मूलों की प्रकृति क्या है?
What is the nature of roots of \(9x^2-24x+16=0\)?
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Correct Answer
A. बराबर वास्तविक मूलEqual real roots
Concept
It is (9x-2-24x+16=(3x-4)2). Therefore both roots are \(\frac{4}{3}\) and \(\frac{4}{3}\), which are equal.
Why this answer is correct
The correct answer is A. बराबर वास्तविक मूल / Equal real roots. It is (9x-2-24x+16=(3x-4)2). Therefore both roots are \(\frac{4}{3}\) and \(\frac{4}{3}\), which are equal.
Exam Tip
यह (9x-2-24x+16=(3x-4)2) है। इसलिए दोनों मूल \(\frac{4}{3}\) और \(\frac{4}{3}\) बराबर हैं।
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