समीकरण \(4x^2-12x+9=0\) के मूलों की प्रकृति क्या है?
What is the nature of roots of \(4x^2-12x+9=0\)?
Explanation opens after your attempt
Correct Answer
A. बराबर वास्तविक मूलEqual real roots
Concept
It is (4x-2-12x+9=(2x-3)2). Therefore both roots are \(\frac{3}{2}\) and \(\frac{3}{2}\), which are equal.
Why this answer is correct
The correct answer is A. बराबर वास्तविक मूल / Equal real roots. It is (4x-2-12x+9=(2x-3)2). Therefore both roots are \(\frac{3}{2}\) and \(\frac{3}{2}\), which are equal.
Exam Tip
यह (4x-2-12x+9=(2x-3)2) है। इसलिए दोनों मूल \(\frac{3}{2}\) और \(\frac{3}{2}\) बराबर हैं।
Login to save your score, XP, coins and progress.