Medium Mathematics Quadratic Equations Class 10 Level 33

समीकरण \(25x^2-30x+9=0\) के मूलों की प्रकृति क्या है?

What is the nature of roots of \(25x^2-30x+9=0\)?

Explanation opens after your attempt
Correct Answer

A. बराबर वास्तविक मूलEqual real roots

Step 1

Concept

It is (25x-2-30x+9=(5x-3)2). Therefore both roots are \(\frac{3}{5}\) and \(\frac{3}{5}\), which are equal.

Step 2

Why this answer is correct

The correct answer is A. बराबर वास्तविक मूल / Equal real roots. It is (25x-2-30x+9=(5x-3)2). Therefore both roots are \(\frac{3}{5}\) and \(\frac{3}{5}\), which are equal.

Step 3

Exam Tip

यह (25x-2-30x+9=(5x-3)2) है। इसलिए दोनों मूल \(\frac{3}{5}\) और \(\frac{3}{5}\) बराबर हैं।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

समीकरण \(25x^2-30x+9=0\) के मूलों की प्रकृति क्या है? / What is the nature of roots of \(25x^2-30x+9=0\)?

Correct Answer: A. बराबर वास्तविक मूल / Equal real roots. Explanation: यह (25x-2-30x+9=(5x-3)2) है। इसलिए दोनों मूल \(\frac{3}{5}\) और \(\frac{3}{5}\) बराबर हैं। / It is (25x-2-30x+9=(5x-3)2). Therefore both roots are \(\frac{3}{5}\) and \(\frac{3}{5}\), which are equal.

Which concept should I revise for this Mathematics MCQ?

It is (25x-2-30x+9=(5x-3)2). Therefore both roots are \(\frac{3}{5}\) and \(\frac{3}{5}\), which are equal.

What exam hint can help solve this Mathematics question?

यह (25x-2-30x+9=(5x-3)2) है। इसलिए दोनों मूल \(\frac{3}{5}\) और \(\frac{3}{5}\) बराबर हैं।

Student Class Required

Select your class first

Quiz questions, daily challenge and practice pages will open according to your selected class. Class 11/12 ke liye stream bhi select karein.