\( 16x^4-81y^4 \) का गुणनखंडों में सही पहला चरण क्या है?

What is the correct first factorization step for \( 16x^4-81y^4 \)?

Explanation opens after your attempt
Correct Answer

A. ( \(4x^2-9y^2\)\(4x^2+9y^2\) )

Step 1

Concept

(16x-4=\(4x^2\)2) and (81y-4=\(9y^2\)2). Exam tip: identify larger squares first.

Step 2

Why this answer is correct

The correct answer is A. ( \(4x^2-9y^2\)\(4x^2+9y^2\) ). (16x-4=\(4x^2\)2) and (81y-4=\(9y^2\)2). Exam tip: identify larger squares first.

Step 3

Exam Tip

(16x-4=\(4x^2\)2) और (81y-4=\(9y^2\)2) है। परीक्षा में पहले बड़े वर्ग पहचानें।

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Mathematics Answer, Explanation and Revision Hints

\( 16x^4-81y^4 \) का गुणनखंडों में सही पहला चरण क्या है? / What is the correct first factorization step for \( 16x^4-81y^4 \)?

Correct Answer: A. ( \(4x^2-9y^2\)\(4x^2+9y^2\) ). Explanation: (16x-4=\(4x^2\)2) और (81y-4=\(9y^2\)2) है। परीक्षा में पहले बड़े वर्ग पहचानें। / (16x-4=\(4x^2\)2) and (81y-4=\(9y^2\)2). Exam tip: identify larger squares first.

Which concept should I revise for this Mathematics MCQ?

(16x-4=\(4x^2\)2) and (81y-4=\(9y^2\)2). Exam tip: identify larger squares first.

What exam hint can help solve this Mathematics question?

(16x-4=\(4x^2\)2) और (81y-4=\(9y^2\)2) है। परीक्षा में पहले बड़े वर्ग पहचानें।

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