समीकरण \(x^2+2px+36=0\) के वास्तविक मूल होने की शर्त कौन-सी है?
What is the condition for \(x^2+2px+36=0\) to have real roots?
Explanation opens after your attempt
Correct Answer
A. \(p\leq -6\) या \(p\geq6\)\(p\leq -6\) or \(p\geq6\)
Concept
For real roots, \(D\geq0\) is required. Here \(4p^2-144\geq0\), so \(p\leq-6\) or \(p\geq6\).
Why this answer is correct
The correct answer is A. \(p\leq -6\) या \(p\geq6\) / \(p\leq -6\) or \(p\geq6\). For real roots, \(D\geq0\) is required. Here \(4p^2-144\geq0\), so \(p\leq-6\) or \(p\geq6\).
Exam Tip
वास्तविक मूलों के लिए \(D\geq0\) होना चाहिए। यहाँ \(4p^2-144\geq0\), इसलिए \(p\leq-6\) या \(p\geq6\)।
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