समीकरण \(x^2+2px+25=0\) के वास्तविक मूल होने की शर्त कौन-सी है?
What is the condition for \(x^2+2px+25=0\) to have real roots?
Explanation opens after your attempt
Correct Answer
A. \(p\leq -5\) या \(p\geq5\)\(p\leq -5\) or \(p\geq5\)
Concept
For real roots, \(D\geq0\) is needed. Here \(4p^2-100\geq0\), so \(p\leq-5\) or \(p\geq5\).
Why this answer is correct
The correct answer is A. \(p\leq -5\) या \(p\geq5\) / \(p\leq -5\) or \(p\geq5\). For real roots, \(D\geq0\) is needed. Here \(4p^2-100\geq0\), so \(p\leq-5\) or \(p\geq5\).
Exam Tip
वास्तविक मूलों के लिए \(D\geq0\) चाहिए। यहाँ \(4p^2-100\geq0\), इसलिए \(p\leq-5\) या \(p\geq5\)।
Login to save your score, XP, coins and progress.