समीकरण \(x^2+2kx+16=0\) के वास्तविक मूल होने की शर्त कौन-सी है?
What is the condition for \(x^2+2kx+16=0\) to have real roots?
Explanation opens after your attempt
Correct Answer
A. \(k\leq -4\) या \(k\geq 4\)\(k\leq -4\) or \(k\geq 4\)
Concept
For real roots, \(D\geq0\) is needed. Here \(4k^2-64\geq0\), so \(k\leq-4\) or \(k\geq4\).
Why this answer is correct
The correct answer is A. \(k\leq -4\) या \(k\geq 4\) / \(k\leq -4\) or \(k\geq 4\). For real roots, \(D\geq0\) is needed. Here \(4k^2-64\geq0\), so \(k\leq-4\) or \(k\geq4\).
Exam Tip
वास्तविक मूलों के लिए \(D\geq0\) चाहिए। यहाँ \(4k^2-64\geq0\), इसलिए \(k\leq-4\) या \(k\geq4\)।
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