(\sec\left\(\frac{\pi}{2}+\theta\right\)) किसके बराबर होता है?
What is (\sec\left\(\frac{\pi}{2}+\theta\right\)) equal to?
Explanation opens after your attempt
Correct Answer
A. -\(\cosec \theta\)
Step 1
Concept
The cofunction of \(\sec \theta\) is \(\cosec \theta\), and \(\sec \theta\) is negative in the second quadrant. Hence the value is \(-\cosec \theta\).
Step 2
Why this answer is correct
The correct answer is A. -\(\cosec \theta\). The cofunction of \(\sec \theta\) is \(\cosec \theta\), and \(\sec \theta\) is negative in the second quadrant. Hence the value is \(-\cosec \theta\).
Step 3
Exam Tip
\(\sec \theta\) का सह-फलन \(\cosec \theta\) है और दूसरे चतुर्थांश में \(\sec \theta\) ऋणात्मक होता है। इसलिए मान \(-\cosec \theta\) है।
Mathematics Answer, Explanation and Revision Hints
(\sec\left\(\frac{\pi}{2}+\theta\right\)) किसके बराबर होता है? / What is (\sec\left\(\frac{\pi}{2}+\theta\right\)) equal to?
Correct Answer: A. -\(\cosec \theta\). Explanation: \(\sec \theta\) का सह-फलन \(\cosec \theta\) है और दूसरे चतुर्थांश में \(\sec \theta\) ऋणात्मक होता है। इसलिए मान \(-\cosec \theta\) है। / The cofunction of \(\sec \theta\) is \(\cosec \theta\), and \(\sec \theta\) is negative in the second quadrant. Hence the value is \(-\cosec \theta\).
Which concept should I revise for this Mathematics MCQ?
The cofunction of \(\sec \theta\) is \(\cosec \theta\), and \(\sec \theta\) is negative in the second quadrant. Hence the value is \(-\cosec \theta\).
What exam hint can help solve this Mathematics question?
\(\sec \theta\) का सह-फलन \(\cosec \theta\) है और दूसरे चतुर्थांश में \(\sec \theta\) ऋणात्मक होता है। इसलिए मान \(-\cosec \theta\) है।
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