\(\frac{x+3}{x}=\frac{16}{x+3}\), \(x\neq0,-3\), के हल क्या हैं?
What are the solutions of \(\frac{x+3}{x}=\frac{16}{x+3}\), \(x\neq0,-3\)?
Explanation opens after your attempt
Correct Answer
A. (x=1,9)
Concept
(x-2-10x+9=(x-1)(x-9)), so (x=1) and (x=9). In exams, check solutions against excluded denominator values.
Why this answer is correct
The correct answer is A. (x=1,9). (x-2-10x+9=(x-1)(x-9)), so (x=1) and (x=9). In exams, check solutions against excluded denominator values.
Exam Tip
(x-2-10x+9=(x-1)(x-9)), इसलिए (x=1) और (x=9) हैं। परीक्षा में हर के निषिद्ध मानों से हलों की जांच करें।
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