\(\frac{x+2}{x}=\frac{9}{x+2}\), \(x\neq0,-2\), के हल क्या हैं?
What are the solutions of \(\frac{x+2}{x}=\frac{9}{x+2}\), \(x\neq0,-2\)?
Explanation opens after your attempt
Correct Answer
A. (x=1,4)
Concept
(x-2-5x+4=(x-1)(x-4)), so (x=1) and (x=4). In exams, check solutions against excluded denominator values.
Why this answer is correct
The correct answer is A. (x=1,4). (x-2-5x+4=(x-1)(x-4)), so (x=1) and (x=4). In exams, check solutions against excluded denominator values.
Exam Tip
(x-2-5x+4=(x-1)(x-4)), इसलिए (x=1) और (x=4) हैं। परीक्षा में हर वाले निषिद्ध मानों से हलों की जांच करें।
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