\(\frac{1}{x}+x=\frac{37}{6}\), \(x\neq0\), के हल क्या हैं?
What are the solutions of \(\frac{1}{x}+x=\frac{37}{6}\), \(x\neq0\)?
Explanation opens after your attempt
Correct Answer
A. \(x=6,\frac{1}{6}\)
Concept
(6x-2-37x+6=(6x-1)(x-6)), so \(x=\frac{1}{6}\) and (6). In exams, check whether obtained roots are valid in the original equation.
Why this answer is correct
The correct answer is A. \(x=6,\frac{1}{6}\). (6x-2-37x+6=(6x-1)(x-6)), so \(x=\frac{1}{6}\) and (6). In exams, check whether obtained roots are valid in the original equation.
Exam Tip
(6x-2-37x+6=(6x-1)(x-6)), इसलिए \(x=\frac{1}{6}\) और (6) हैं। परीक्षा में प्राप्त हल मूल समीकरण में मान्य हैं या नहीं जांचें।
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