\(\frac{1}{x}+x=\frac{17}{4}\), \(x\neq0\), के हल क्या हैं?
What are the solutions of \(\frac{1}{x}+x=\frac{17}{4}\), \(x\neq0\)?
Explanation opens after your attempt
Correct Answer
A. \(x=4,\frac{1}{4}\)
Concept
(4x-2-17x+4=(4x-1)(x-4)), so \(x=\frac{1}{4}\) and (4). In exams, check whether obtained roots are valid in the original equation.
Why this answer is correct
The correct answer is A. \(x=4,\frac{1}{4}\). (4x-2-17x+4=(4x-1)(x-4)), so \(x=\frac{1}{4}\) and (4). In exams, check whether obtained roots are valid in the original equation.
Exam Tip
(4x-2-17x+4=(4x-1)(x-4)), इसलिए \(x=\frac{1}{4}\) और (4) हैं। परीक्षा में मिले हल मूल समीकरण में मान्य हैं या नहीं जांचें।
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