Medium Mathematics Quadratic Equations Class 10 Level 32

समीकरण \(8x^2-10x+3=0\) के मूल कौन से हैं?

What are the roots of \(8x^2-10x+3=0\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{1}{2}\) और \(\frac{3}{4}\)\(\frac{1}{2}\) and \(\frac{3}{4}\)

Step 1

Concept

(8x-2-10x+3=(2x-1)(4x-3)). Therefore the roots are \(\frac{1}{2}\) and \(\frac{3}{4}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{1}{2}\) और \(\frac{3}{4}\) / \(\frac{1}{2}\) and \(\frac{3}{4}\). (8x-2-10x+3=(2x-1)(4x-3)). Therefore the roots are \(\frac{1}{2}\) and \(\frac{3}{4}\).

Step 3

Exam Tip

(8x-2-10x+3=(2x-1)(4x-3)) है। इसलिए मूल \(\frac{1}{2}\) और \(\frac{3}{4}\) हैं।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(8x^2-10x+3=0\) के मूल कौन से हैं? / What are the roots of \(8x^2-10x+3=0\)?

Correct Answer: A. \(\frac{1}{2}\) और \(\frac{3}{4}\) / \(\frac{1}{2}\) and \(\frac{3}{4}\). Explanation: (8x-2-10x+3=(2x-1)(4x-3)) है। इसलिए मूल \(\frac{1}{2}\) और \(\frac{3}{4}\) हैं। / (8x-2-10x+3=(2x-1)(4x-3)). Therefore the roots are \(\frac{1}{2}\) and \(\frac{3}{4}\).

Which concept should I revise for this Mathematics MCQ?

(8x-2-10x+3=(2x-1)(4x-3)). Therefore the roots are \(\frac{1}{2}\) and \(\frac{3}{4}\).

What exam hint can help solve this Mathematics question?

(8x-2-10x+3=(2x-1)(4x-3)) है। इसलिए मूल \(\frac{1}{2}\) और \(\frac{3}{4}\) हैं।

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