समीकरण \(6x^2-7x+2=0\) के मूल कौन से हैं?
What are the roots of \(6x^2-7x+2=0\)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{1}{2}\) और \(\frac{2}{3}\)\(\frac{1}{2}\) and \(\frac{2}{3}\)
Concept
(6x-2-7x+2=(3x-2)(2x-1)). Therefore the roots are \(\frac{2}{3}\) and \(\frac{1}{2}\).
Why this answer is correct
The correct answer is A. \(\frac{1}{2}\) और \(\frac{2}{3}\) / \(\frac{1}{2}\) and \(\frac{2}{3}\). (6x-2-7x+2=(3x-2)(2x-1)). Therefore the roots are \(\frac{2}{3}\) and \(\frac{1}{2}\).
Exam Tip
(6x-2-7x+2=(3x-2)(2x-1)) है। इसलिए मूल \(\frac{2}{3}\) और \(\frac{1}{2}\) हैं।
Login to save your score, XP, coins and progress.