समीकरण \(49x^2-64=0\) के मूल क्या हैं?
What are the roots of \(49x^2-64=0\)?
Explanation opens after your attempt
A. \(x=\pm \frac{8}{7}\)
Concept
\(49x^2=64\), so \(x^2=\frac{64}{49}\) and \(x=\pm\frac{8}{7}\). Take both signs while taking square roots.
Why this answer is correct
The correct answer is A. \(x=\pm \frac{8}{7}\). \(49x^2=64\), so \(x^2=\frac{64}{49}\) and \(x=\pm\frac{8}{7}\). Take both signs while taking square roots.
Exam Tip
\(49x^2=64\), इसलिए \(x^2=\frac{64}{49}\) और \(x=\pm\frac{8}{7}\) है। वर्गमूल लेते समय दोनों चिन्ह लें।
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