Medium Mathematics Quadratic Equations Class 10 Level 30

समीकरण \(49x^2-64=0\) के मूल क्या हैं?

What are the roots of \(49x^2-64=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm \frac{8}{7}\)

Step 1

Concept

\(49x^2=64\), so \(x^2=\frac{64}{49}\) and \(x=\pm\frac{8}{7}\). Take both signs while taking square roots.

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm \frac{8}{7}\). \(49x^2=64\), so \(x^2=\frac{64}{49}\) and \(x=\pm\frac{8}{7}\). Take both signs while taking square roots.

Step 3

Exam Tip

\(49x^2=64\), इसलिए \(x^2=\frac{64}{49}\) और \(x=\pm\frac{8}{7}\) है। वर्गमूल लेते समय दोनों चिन्ह लें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

समीकरण \(49x^2-64=0\) के मूल क्या हैं? / What are the roots of \(49x^2-64=0\)?

Correct Answer: A. \(x=\pm \frac{8}{7}\). Explanation: \(49x^2=64\), इसलिए \(x^2=\frac{64}{49}\) और \(x=\pm\frac{8}{7}\) है। वर्गमूल लेते समय दोनों चिन्ह लें। / \(49x^2=64\), so \(x^2=\frac{64}{49}\) and \(x=\pm\frac{8}{7}\). Take both signs while taking square roots.

Which concept should I revise for this Mathematics MCQ?

\(49x^2=64\), so \(x^2=\frac{64}{49}\) and \(x=\pm\frac{8}{7}\). Take both signs while taking square roots.

What exam hint can help solve this Mathematics question?

\(49x^2=64\), इसलिए \(x^2=\frac{64}{49}\) और \(x=\pm\frac{8}{7}\) है। वर्गमूल लेते समय दोनों चिन्ह लें।

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