समीकरण \(16x^2-81=0\) के मूल क्या हैं?
What are the roots of \(16x^2-81=0\)?
Explanation opens after your attempt
Correct Answer
A. \(x=\pm \frac{9}{4}\)
Concept
\(16x^2=81\), so \(x^2=\frac{81}{16}\) and \(x=\pm\frac{9}{4}\). Take both signs while taking square roots.
Why this answer is correct
The correct answer is A. \(x=\pm \frac{9}{4}\). \(16x^2=81\), so \(x^2=\frac{81}{16}\) and \(x=\pm\frac{9}{4}\). Take both signs while taking square roots.
Exam Tip
\(16x^2=81\), इसलिए \(x^2=\frac{81}{16}\) और \(x=\pm\frac{9}{4}\) है। वर्गमूल लेते समय दोनों चिन्ह लें।
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