अंकों (0,1,2,3,4,5,6,7,8) से बिना पुनरावृत्ति (4)-अंकीय ऐसी संख्याएं बनानी हैं जो (5) से विभाज्य हों। कुल संख्याएं कितनी बनेंगी?
Using the digits (0,1,2,3,4,5,6,7,8) without repetition (4)-digit numbers divisible by (5) are to be formed. How many numbers can be formed?
Explanation opens after your attempt
C. (630) संख्याएं(630) numbers
Concept
If the last digit is (0) there are \(8 \times 7 \times 6=336\) ways and if the last digit is (5) there are \(7 \times 7 \times 6=294\) ways. The total is (336+294=630).
Why this answer is correct
The correct answer is C. (630) संख्याएं / (630) numbers. If the last digit is (0) there are \(8 \times 7 \times 6=336\) ways and if the last digit is (5) there are \(7 \times 7 \times 6=294\) ways. The total is (336+294=630).
Exam Tip
अंतिम अंक (0) हो तो \(8 \times 7 \times 6=336\) तरीके और अंतिम अंक (5) हो तो \(7 \times 7 \times 6=294\) तरीके हैं। कुल (336+294=630) है।
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