Medium Mathematics Quadratic Equations Class 10 Level 30

दो क्रमागत धनात्मक पूर्णांकों के वर्गों का योग (145) है। यदि छोटा पूर्णांक (x) है, तो समीकरण कौन-सा है?

The sum of squares of two consecutive positive integers is (145). If the smaller integer is (x), which equation is correct?

Explanation opens after your attempt
Correct Answer

A. \(2x^2+2x-144=0\)

Step 1

Concept

The integers are (x) and (x+1), so (x-2+(x+1)2=145). Simplifying gives \(2x^2+2x-144=0\).

Step 2

Why this answer is correct

The correct answer is A. \(2x^2+2x-144=0\). The integers are (x) and (x+1), so (x-2+(x+1)2=145). Simplifying gives \(2x^2+2x-144=0\).

Step 3

Exam Tip

पूर्णांक (x) और (x+1) होंगे, इसलिए (x-2+(x+1)2=145)। सरल करने पर \(2x^2+2x-144=0\) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

दो क्रमागत धनात्मक पूर्णांकों के वर्गों का योग (145) है। यदि छोटा पूर्णांक (x) है, तो समीकरण कौन-सा है? / The sum of squares of two consecutive positive integers is (145). If the smaller integer is (x), which equation is correct?

Correct Answer: A. \(2x^2+2x-144=0\). Explanation: पूर्णांक (x) और (x+1) होंगे, इसलिए (x-2+(x+1)2=145)। सरल करने पर \(2x^2+2x-144=0\) मिलता है। / The integers are (x) and (x+1), so (x-2+(x+1)2=145). Simplifying gives \(2x^2+2x-144=0\).

Which concept should I revise for this Mathematics MCQ?

The integers are (x) and (x+1), so (x-2+(x+1)2=145). Simplifying gives \(2x^2+2x-144=0\).

What exam hint can help solve this Mathematics question?

पूर्णांक (x) और (x+1) होंगे, इसलिए (x-2+(x+1)2=145)। सरल करने पर \(2x^2+2x-144=0\) मिलता है।

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