On which interval is \(\sin^{-1}x\) an increasing function?
Explanation opens after your attempt
Correct Answer
A. \(\left[-1,1\right]\)
Step 1
Concept
The function \(\sin^{-1}x\) is increasing on its whole domain \(\left[-1,1\right]\). This matches the chosen branch of \(\sin x\).
Step 2
Why this answer is correct
The correct answer is A. \(\left[-1,1\right]\). The function \(\sin^{-1}x\) is increasing on its whole domain \(\left[-1,1\right]\). This matches the chosen branch of \(\sin x\).
Step 3
Exam Tip
\(\sin^{-1}x\) अपने पूरे प्रांत \(\left[-1,1\right]\) पर बढ़ता है। यह \(\sin x\) की चुनी गई शाखा से मिलता है।
Mathematics Answer, Explanation and Revision Hints
\(\sin^{-1}x\) किस अंतराल पर बढ़ता हुआ फलन है? / On which interval is \(\sin^{-1}x\) an increasing function?
Correct Answer: A. \(\left[-1,1\right]\). Explanation: \(\sin^{-1}x\) अपने पूरे प्रांत \(\left[-1,1\right]\) पर बढ़ता है। यह \(\sin x\) की चुनी गई शाखा से मिलता है। / The function \(\sin^{-1}x\) is increasing on its whole domain \(\left[-1,1\right]\). This matches the chosen branch of \(\sin x\).
Which concept should I revise for this Mathematics MCQ?
The function \(\sin^{-1}x\) is increasing on its whole domain \(\left[-1,1\right]\). This matches the chosen branch of \(\sin x\).
What exam hint can help solve this Mathematics question?
\(\sin^{-1}x\) अपने पूरे प्रांत \(\left[-1,1\right]\) पर बढ़ता है। यह \(\sin x\) की चुनी गई शाखा से मिलता है।
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