यदि \(y=\sqrt{18}+\sqrt{50}-\sqrt{8}\) है तो \(y^2\) का मान क्या है?
If \(y=\sqrt{18}+\sqrt{50}-\sqrt{8}\), what is the value of \(y^2\)?
Explanation opens after your attempt
Correct Answer
A. (72)
Concept
\(\sqrt{18}=3\sqrt{2}\), \(\sqrt{50}=5\sqrt{2}\), and \(\sqrt{8}=2\sqrt{2}\), so \(y=6\sqrt{2}\). Its square is (72).
Why this answer is correct
The correct answer is A. (72). \(\sqrt{18}=3\sqrt{2}\), \(\sqrt{50}=5\sqrt{2}\), and \(\sqrt{8}=2\sqrt{2}\), so \(y=6\sqrt{2}\). Its square is (72).
Exam Tip
\(\sqrt{18}=3\sqrt{2}\), \(\sqrt{50}=5\sqrt{2}\) और \(\sqrt{8}=2\sqrt{2}\), इसलिए \(y=6\sqrt{2}\)। वर्ग (72) होगा।
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