यदि \(x=\sqrt{7}+\sqrt{3}\) है तो \(x^2-10\) का मान क्या है?
If \(x=\sqrt{7}+\sqrt{3}\), what is the value of \(x^2-10\)?
Explanation opens after your attempt
A. \(2\sqrt{21}\)
Concept
\(x^2=7+3+2\sqrt{21}=10+2\sqrt{21}\). Therefore \(x^2-10=2\sqrt{21}\).
Why this answer is correct
The correct answer is A. \(2\sqrt{21}\). \(x^2=7+3+2\sqrt{21}=10+2\sqrt{21}\). Therefore \(x^2-10=2\sqrt{21}\).
Exam Tip
\(x^2=7+3+2\sqrt{21}=10+2\sqrt{21}\) है। इसलिए \(x^2-10=2\sqrt{21}\) होगा।
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