यदि \(x=\sqrt{3}+\sqrt{2}\) है तो \(x^2-5\) का मान क्या है?
If \(x=\sqrt{3}+\sqrt{2}\), what is the value of \(x^2-5\)?
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{6}\)
Concept
\(x^2=3+2+2\sqrt{6}=5+2\sqrt{6}\). Therefore \(x^2-5=2\sqrt{6}\).
Why this answer is correct
The correct answer is A. \(2\sqrt{6}\). \(x^2=3+2+2\sqrt{6}=5+2\sqrt{6}\). Therefore \(x^2-5=2\sqrt{6}\).
Exam Tip
\(x^2=3+2+2\sqrt{6}=5+2\sqrt{6}\) है। इसलिए \(x^2-5=2\sqrt{6}\) है।
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