Hard Mathematics Polynomials Class 10 Level 26

यदि \(x=\sqrt{2}+\sqrt{3}\), तो \(x^2\) का सही रूप क्या है?

If \(x=\sqrt{2}+\sqrt{3}\), what is the correct form of \(x^2\)?

Explanation opens after your attempt
Correct Answer

A. \(5+2\sqrt{6}\)

Step 1

Concept

(\(\sqrt{2}+\sqrt{3}\)2=2+3+2\sqrt{6}=5+2\sqrt{6}). Do not miss the middle term (2ab) in exams.

Step 2

Why this answer is correct

The correct answer is A. \(5+2\sqrt{6}\). (\(\sqrt{2}+\sqrt{3}\)2=2+3+2\sqrt{6}=5+2\sqrt{6}). Do not miss the middle term (2ab) in exams.

Step 3

Exam Tip

(\(\sqrt{2}+\sqrt{3}\)2=2+3+2\sqrt{6}=5+2\sqrt{6}) है। परीक्षा में बीच का पद (2ab) न छोड़ें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(x=\sqrt{2}+\sqrt{3}\), तो \(x^2\) का सही रूप क्या है? / If \(x=\sqrt{2}+\sqrt{3}\), what is the correct form of \(x^2\)?

Correct Answer: A. \(5+2\sqrt{6}\). Explanation: (\(\sqrt{2}+\sqrt{3}\)2=2+3+2\sqrt{6}=5+2\sqrt{6}) है। परीक्षा में बीच का पद (2ab) न छोड़ें। / (\(\sqrt{2}+\sqrt{3}\)2=2+3+2\sqrt{6}=5+2\sqrt{6}). Do not miss the middle term (2ab) in exams.

Which concept should I revise for this Mathematics MCQ?

(\(\sqrt{2}+\sqrt{3}\)2=2+3+2\sqrt{6}=5+2\sqrt{6}). Do not miss the middle term (2ab) in exams.

What exam hint can help solve this Mathematics question?

(\(\sqrt{2}+\sqrt{3}\)2=2+3+2\sqrt{6}=5+2\sqrt{6}) है। परीक्षा में बीच का पद (2ab) न छोड़ें।

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