Hard Mathematics Polynomials Class 10 Level 26

यदि \(x=\frac{2}{\sqrt{3}+1}\), तो (x) किसके बराबर है?

If \(x=\frac{2}{\sqrt{3}+1}\), what is (x) equal to?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{3}-1\)

Step 1

Concept

(\frac{2}{\sqrt{3}+1}\times\frac{\sqrt{3}-1}{\sqrt{3}-1}=\frac{2\(\sqrt{3}-1\)}{2}=\sqrt{3}-1). The conjugate makes the denominator rational.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{3}-1\). (\frac{2}{\sqrt{3}+1}\times\frac{\sqrt{3}-1}{\sqrt{3}-1}=\frac{2\(\sqrt{3}-1\)}{2}=\sqrt{3}-1). The conjugate makes the denominator rational.

Step 3

Exam Tip

(\frac{2}{\sqrt{3}+1}\times\frac{\sqrt{3}-1}{\sqrt{3}-1}=\frac{2\(\sqrt{3}-1\)}{2}=\sqrt{3}-1) है। परीक्षा में संयुग्मी से हर परिमेय बनता है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(x=\frac{2}{\sqrt{3}+1}\), तो (x) किसके बराबर है? / If \(x=\frac{2}{\sqrt{3}+1}\), what is (x) equal to?

Correct Answer: A. \(\sqrt{3}-1\). Explanation: (\frac{2}{\sqrt{3}+1}\times\frac{\sqrt{3}-1}{\sqrt{3}-1}=\frac{2\(\sqrt{3}-1\)}{2}=\sqrt{3}-1) है। परीक्षा में संयुग्मी से हर परिमेय बनता है। / (\frac{2}{\sqrt{3}+1}\times\frac{\sqrt{3}-1}{\sqrt{3}-1}=\frac{2\(\sqrt{3}-1\)}{2}=\sqrt{3}-1). The conjugate makes the denominator rational.

Which concept should I revise for this Mathematics MCQ?

(\frac{2}{\sqrt{3}+1}\times\frac{\sqrt{3}-1}{\sqrt{3}-1}=\frac{2\(\sqrt{3}-1\)}{2}=\sqrt{3}-1). The conjugate makes the denominator rational.

What exam hint can help solve this Mathematics question?

(\frac{2}{\sqrt{3}+1}\times\frac{\sqrt{3}-1}{\sqrt{3}-1}=\frac{2\(\sqrt{3}-1\)}{2}=\sqrt{3}-1) है। परीक्षा में संयुग्मी से हर परिमेय बनता है।

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