Hard Mathematics Polynomials Class 10 Level 26

यदि \(x=\frac{1}{\sqrt{5}-2}\), तो (x) का सरल रूप क्या है?

If \(x=\frac{1}{\sqrt{5}-2}\), what is the simplified form of (x)?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{5}+2\)

Step 1

Concept

\(\frac{1}{\sqrt{5}-2}\times\frac{\sqrt{5}+2}{\sqrt{5}+2}=\frac{\sqrt{5}+2}{5-4}=\sqrt{5}+2\). Rationalise the denominator in exams.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{5}+2\). \(\frac{1}{\sqrt{5}-2}\times\frac{\sqrt{5}+2}{\sqrt{5}+2}=\frac{\sqrt{5}+2}{5-4}=\sqrt{5}+2\). Rationalise the denominator in exams.

Step 3

Exam Tip

\(\frac{1}{\sqrt{5}-2}\times\frac{\sqrt{5}+2}{\sqrt{5}+2}=\frac{\sqrt{5}+2}{5-4}=\sqrt{5}+2\) है। परीक्षा में हर का परिमेयकरण करें।

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(x=\frac{1}{\sqrt{5}-2}\), तो (x) का सरल रूप क्या है? / If \(x=\frac{1}{\sqrt{5}-2}\), what is the simplified form of (x)?

Correct Answer: A. \(\sqrt{5}+2\). Explanation: \(\frac{1}{\sqrt{5}-2}\times\frac{\sqrt{5}+2}{\sqrt{5}+2}=\frac{\sqrt{5}+2}{5-4}=\sqrt{5}+2\) है। परीक्षा में हर का परिमेयकरण करें। / \(\frac{1}{\sqrt{5}-2}\times\frac{\sqrt{5}+2}{\sqrt{5}+2}=\frac{\sqrt{5}+2}{5-4}=\sqrt{5}+2\). Rationalise the denominator in exams.

Which concept should I revise for this Mathematics MCQ?

\(\frac{1}{\sqrt{5}-2}\times\frac{\sqrt{5}+2}{\sqrt{5}+2}=\frac{\sqrt{5}+2}{5-4}=\sqrt{5}+2\). Rationalise the denominator in exams.

What exam hint can help solve this Mathematics question?

\(\frac{1}{\sqrt{5}-2}\times\frac{\sqrt{5}+2}{\sqrt{5}+2}=\frac{\sqrt{5}+2}{5-4}=\sqrt{5}+2\) है। परीक्षा में हर का परिमेयकरण करें।

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