Expert Mathematics Polynomials Class 10 Level 27

यदि \(x=3+\sqrt{8}\), तो (x) किस द्विघात बहुपद का शून्यक हो सकता है?

If \(x=3+\sqrt{8}\), which quadratic polynomial can have (x) as a zero?

Explanation opens after your attempt
Correct Answer

A. \(x^2-6x+1\)

Step 1

Concept

The companion zero is \(3-\sqrt{8}\). Sum (6) and product (9-8=1) form \(x^2-6x+1\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-6x+1\). The companion zero is \(3-\sqrt{8}\). Sum (6) and product (9-8=1) form \(x^2-6x+1\).

Step 3

Exam Tip

साथी शून्यक \(3-\sqrt{8}\) है। योग (6) और गुणनफल (9-8=1) से बहुपद \(x^2-6x+1\) बनता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x=3+\sqrt{8}\), तो (x) किस द्विघात बहुपद का शून्यक हो सकता है? / If \(x=3+\sqrt{8}\), which quadratic polynomial can have (x) as a zero?

Correct Answer: A. \(x^2-6x+1\). Explanation: साथी शून्यक \(3-\sqrt{8}\) है। योग (6) और गुणनफल (9-8=1) से बहुपद \(x^2-6x+1\) बनता है। / The companion zero is \(3-\sqrt{8}\). Sum (6) and product (9-8=1) form \(x^2-6x+1\).

Which concept should I revise for this Mathematics MCQ?

The companion zero is \(3-\sqrt{8}\). Sum (6) and product (9-8=1) form \(x^2-6x+1\).

What exam hint can help solve this Mathematics question?

साथी शून्यक \(3-\sqrt{8}\) है। योग (6) और गुणनफल (9-8=1) से बहुपद \(x^2-6x+1\) बनता है।

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