यदि (x=-2) समीकरण \(x^2+px-6=0\) का मूल है, तो (p) का मान क्या होगा?
If (x=-2) is a root of \(x^2+px-6=0\), what is the value of (p)?
Explanation opens after your attempt
Correct Answer
B. (-1)
Concept
Putting (x=-2) gives (4-2p-6=0), so (p=-1). When a root is given, use substitution.
Why this answer is correct
The correct answer is B. (-1). Putting (x=-2) gives (4-2p-6=0), so (p=-1). When a root is given, use substitution.
Exam Tip
(x=-2) रखने पर (4-2p-6=0), इसलिए (p=-1) मिलता है। मूल दिया हो तो प्रतिस्थापन करें।
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