यदि \(x^2+px+q\) के शून्यक \(7+2\sqrt{3}\) और \(7-2\sqrt{3}\) हैं, तो (p+q) क्या है?
If the zeroes of \(x^2+px+q\) are \(7+2\sqrt{3}\) and \(7-2\sqrt{3}\), what is (p+q)?
Explanation opens after your attempt
Correct Answer
A. (23)
Concept
The sum is (14), so (p=-14), and the product is (49-12=37), so (q=37). Hence (p+q=23).
Why this answer is correct
The correct answer is A. (23). The sum is (14), so (p=-14), and the product is (49-12=37), so (q=37). Hence (p+q=23).
Exam Tip
योग (14) है, इसलिए (p=-14), और गुणनफल (49-12=37) है, इसलिए (q=37)। अतः (p+q=23) है।
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