यदि ग्राफ के (x)-अक्ष कटान ((s-4,0)), ((s+1,0)), ((s+7,0)) हैं, तो शून्यकों का माध्य क्या है?
If the (x)-axis intersections of a graph are ((s-4,0)), ((s+1,0)), ((s+7,0)), what is the mean of the zeroes?
Explanation opens after your attempt
Correct Answer
A. \(s+\frac{4}{3}\)
Concept
The mean is (\frac{(s-4)+(s+1)+(s+7)}{3}=s+\frac{4}{3}). Tip: take the average even for symbolic zeroes.
Why this answer is correct
The correct answer is A. \(s+\frac{4}{3}\). The mean is (\frac{(s-4)+(s+1)+(s+7)}{3}=s+\frac{4}{3}). Tip: take the average even for symbolic zeroes.
Exam Tip
माध्य (\frac{(s-4)+(s+1)+(s+7)}{3}=s+\frac{4}{3}) है। टिप: प्रतीकात्मक शून्यकों में भी औसत लें।
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