यदि ग्राफ के (x)-अक्ष कटान ((r-1,0)), ((r+2,0)), ((r+5,0)) हैं, तो शून्यकों का माध्य क्या है?
If the (x)-axis intersections of a graph are ((r-1,0)), ((r+2,0)), ((r+5,0)), what is the mean of the zeroes?
Explanation opens after your attempt
A. (r+2)
Concept
The mean is (\frac{(r-1)+(r+2)+(r+5)}{3}=r+2). Tip: take the average even for symbolic zeroes.
Why this answer is correct
The correct answer is A. (r+2). The mean is (\frac{(r-1)+(r+2)+(r+5)}{3}=r+2). Tip: take the average even for symbolic zeroes.
Exam Tip
माध्य (\frac{(r-1)+(r+2)+(r+5)}{3}=r+2) है। टिप: प्रतीकात्मक शून्यकों में भी औसत लें।
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