यदि \(x^2+rx+36=0\) के मूल (6) और (6) हैं, तो (r) का मान क्या होगा?
If the roots of \(x^2+rx+36=0\) are (6) and (6), what is the value of (r)?
Explanation opens after your attempt
Correct Answer
B. (-12)
Concept
The sum of roots is (12), and in \(x^2+rx+36=0\) the sum is (-r). Therefore (r=-12).
Why this answer is correct
The correct answer is B. (-12). The sum of roots is (12), and in \(x^2+rx+36=0\) the sum is (-r). Therefore (r=-12).
Exam Tip
मूलों का योग (12) है और \(x^2+rx+36=0\) में योग (-r) होता है। इसलिए (r=-12) है।
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