यदि \(x^2+px+16=0\) के मूल (4) और (4) हैं, तो (p) का मान क्या होगा?
If the roots of \(x^2+px+16=0\) are (4) and (4), what is the value of (p)?
Explanation opens after your attempt
Correct Answer
B. (-8)
Concept
The sum of roots is (8), and in \(x^2+px+16=0\) the sum is (-p). Therefore (p=-8).
Why this answer is correct
The correct answer is B. (-8). The sum of roots is (8), and in \(x^2+px+16=0\) the sum is (-p). Therefore (p=-8).
Exam Tip
मूलों का योग (8) है और \(x^2+px+16=0\) में योग (-p) होता है। इसलिए (p=-8) है।
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