Expert Mathematics Quadratic Equations Class 10 Level 33

यदि \(x^2+ax+b=0\) की जड़ें \(4+\sqrt{7}\) और \(4-\sqrt{7}\) हैं, तो (a+b) का मान क्या है?

If the roots of \(x^2+ax+b=0\) are \(4+\sqrt{7}\) and \(4-\sqrt{7}\), what is (a+b)?

Explanation opens after your attempt
Correct Answer

B. (1)

Step 1

Concept

The sum of roots is (8), so (a=-8). The product is (9), so (b=9), hence (a+b=1).

Step 2

Why this answer is correct

The correct answer is B. (1). The sum of roots is (8), so (a=-8). The product is (9), so (b=9), hence (a+b=1).

Step 3

Exam Tip

जड़ों का योग (8) है, इसलिए (a=-8)। गुणनफल (9) है, इसलिए (b=9), अतः (a+b=1)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2+ax+b=0\) की जड़ें \(4+\sqrt{7}\) और \(4-\sqrt{7}\) हैं, तो (a+b) का मान क्या है? / If the roots of \(x^2+ax+b=0\) are \(4+\sqrt{7}\) and \(4-\sqrt{7}\), what is (a+b)?

Correct Answer: B. (1). Explanation: जड़ों का योग (8) है, इसलिए (a=-8)। गुणनफल (9) है, इसलिए (b=9), अतः (a+b=1)। / The sum of roots is (8), so (a=-8). The product is (9), so (b=9), hence (a+b=1).

Which concept should I revise for this Mathematics MCQ?

The sum of roots is (8), so (a=-8). The product is (9), so (b=9), hence (a+b=1).

What exam hint can help solve this Mathematics question?

जड़ों का योग (8) है, इसलिए (a=-8)। गुणनफल (9) है, इसलिए (b=9), अतः (a+b=1)।

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