यदि \(x^2+ax+b=0\) की जड़ें \(3+\sqrt{2}\) और \(3-\sqrt{2}\) हैं, तो (a+b) का मान क्या है?
If the roots of \(x^2+ax+b=0\) are \(3+\sqrt{2}\) and \(3-\sqrt{2}\), what is (a+b)?
Explanation opens after your attempt
Correct Answer
B. (1)
Concept
The sum of roots is (6), so (a=-6). The product is (7), so (b=7), hence (a+b=1).
Why this answer is correct
The correct answer is B. (1). The sum of roots is (6), so (a=-6). The product is (7), so (b=7), hence (a+b=1).
Exam Tip
जड़ों का योग (6) है, इसलिए (a=-6)। गुणनफल (7) है, इसलिए (b=7), अतः (a+b=1)।
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