Expert Mathematics Quadratic Equations Class 10 Level 31

यदि \(x^2+ax+b=0\) की जड़ें \(2+\sqrt{3}\) और \(2-\sqrt{3}\) हैं, तो (a+b) का मान क्या है?

If the roots of \(x^2+ax+b=0\) are \(2+\sqrt{3}\) and \(2-\sqrt{3}\), what is (a+b)?

Explanation opens after your attempt
Correct Answer

A. (-3)

Step 1

Concept

The sum of roots is (4), so (a=-4). The product is (1), so (b=1), hence (a+b=-3).

Step 2

Why this answer is correct

The correct answer is A. (-3). The sum of roots is (4), so (a=-4). The product is (1), so (b=1), hence (a+b=-3).

Step 3

Exam Tip

जड़ों का योग (4) है, इसलिए (a=-4)। गुणनफल (1) है, इसलिए (b=1), अतः (a+b=-3)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2+ax+b=0\) की जड़ें \(2+\sqrt{3}\) और \(2-\sqrt{3}\) हैं, तो (a+b) का मान क्या है? / If the roots of \(x^2+ax+b=0\) are \(2+\sqrt{3}\) and \(2-\sqrt{3}\), what is (a+b)?

Correct Answer: A. (-3). Explanation: जड़ों का योग (4) है, इसलिए (a=-4)। गुणनफल (1) है, इसलिए (b=1), अतः (a+b=-3)। / The sum of roots is (4), so (a=-4). The product is (1), so (b=1), hence (a+b=-3).

Which concept should I revise for this Mathematics MCQ?

The sum of roots is (4), so (a=-4). The product is (1), so (b=1), hence (a+b=-3).

What exam hint can help solve this Mathematics question?

जड़ों का योग (4) है, इसलिए (a=-4)। गुणनफल (1) है, इसलिए (b=1), अतः (a+b=-3)।

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