यदि \(x^2-9x+c=0\) के मूलों का अनुपात (1:2) है तो (c) का मान क्या है?
If the roots of \(x^2-9x+c=0\) are in the ratio (1:2), what is the value of (c)?
Explanation opens after your attempt
Correct Answer
A. (18)
Concept
Let the roots be (t) and (2t). From (3t=9), (t=3), so the roots are (3) and (6), hence (c=18).
Why this answer is correct
The correct answer is A. (18). Let the roots be (t) and (2t). From (3t=9), (t=3), so the roots are (3) and (6), hence (c=18).
Exam Tip
मूल (t) और (2t) मानें तो (3t=9) से (t=3) है। मूल (3) और (6) होंगे इसलिए (c=18) है।
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