Hard Mathematics Quadratic Equations Class 10 Level 31

यदि \(x^2-6x+c=0\) के मूलों का अनुपात (1:2) है तो (c) का मान क्या है?

If the roots of \(x^2-6x+c=0\) are in the ratio (1:2), what is the value of (c)?

Explanation opens after your attempt
Correct Answer

A. (8)

Step 1

Concept

Let the roots be (t) and (2t). From sum (3t=6), (t=2), so roots are (2) and (4), hence (c=8).

Step 2

Why this answer is correct

The correct answer is A. (8). Let the roots be (t) and (2t). From sum (3t=6), (t=2), so roots are (2) and (4), hence (c=8).

Step 3

Exam Tip

मूल (t) और (2t) मानें तो योग (3t=6) से (t=2) है। मूल (2) और (4) होंगे इसलिए (c=8) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2-6x+c=0\) के मूलों का अनुपात (1:2) है तो (c) का मान क्या है? / If the roots of \(x^2-6x+c=0\) are in the ratio (1:2), what is the value of (c)?

Correct Answer: A. (8). Explanation: मूल (t) और (2t) मानें तो योग (3t=6) से (t=2) है। मूल (2) और (4) होंगे इसलिए (c=8) है। / Let the roots be (t) and (2t). From sum (3t=6), (t=2), so roots are (2) and (4), hence (c=8).

Which concept should I revise for this Mathematics MCQ?

Let the roots be (t) and (2t). From sum (3t=6), (t=2), so roots are (2) and (4), hence (c=8).

What exam hint can help solve this Mathematics question?

मूल (t) और (2t) मानें तो योग (3t=6) से (t=2) है। मूल (2) और (4) होंगे इसलिए (c=8) है।

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