यदि \(x^2-6x+c=0\) के मूलों का अनुपात (1:2) है तो (c) का मान क्या है?
If the roots of \(x^2-6x+c=0\) are in the ratio (1:2), what is the value of (c)?
Explanation opens after your attempt
A. (8)
Concept
Let the roots be (t) and (2t). From sum (3t=6), (t=2), so roots are (2) and (4), hence (c=8).
Why this answer is correct
The correct answer is A. (8). Let the roots be (t) and (2t). From sum (3t=6), (t=2), so roots are (2) and (4), hence (c=8).
Exam Tip
मूल (t) और (2t) मानें तो योग (3t=6) से (t=2) है। मूल (2) और (4) होंगे इसलिए (c=8) है।
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