यदि \(x^2-23x+126=0\) के मूल \(\alpha\) और \(\beta\) हैं, तो \(\alpha^2+\beta^2\) क्या होगा?
If the roots of \(x^2-23x+126=0\) are \(\alpha\) and \(\beta\), what is \(\alpha^2+\beta^2\)?
Explanation opens after your attempt
Correct Answer
A. (277)
Concept
\(\alpha+\beta=23\) and \(\alpha\beta=126\), so (\alpha-2+\beta-2=232-2(126)=277). In exams, remember (\(\alpha+\beta\)2-2\alpha\beta).
Why this answer is correct
The correct answer is A. (277). \(\alpha+\beta=23\) and \(\alpha\beta=126\), so (\alpha-2+\beta-2=232-2(126)=277). In exams, remember (\(\alpha+\beta\)2-2\alpha\beta).
Exam Tip
\(\alpha+\beta=23\) और \(\alpha\beta=126\), इसलिए (\alpha-2+\beta-2=232-2(126)=277) है। परीक्षा में (\(\alpha+\beta\)2-2\alpha\beta) याद रखें।
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