यदि \(3x^2+px+12=0\) की जड़ें (1:4) के अनुपात में हैं, तो (p) के संभव मान क्या हैं?
If the roots of \(3x^2+px+12=0\) are in the ratio (1:4), what are the possible values of (p)?
Explanation opens after your attempt
Correct Answer
A. (15) या (-15)(15) or (-15)
Concept
Let the roots be (r) and (4r). Then \(4r^2=4\), so \(r=\pm1\); using \(5r=-\frac{p}{3}\), we get \(p=\pm15\).
Why this answer is correct
The correct answer is A. (15) या (-15) / (15) or (-15). Let the roots be (r) and (4r). Then \(4r^2=4\), so \(r=\pm1\); using \(5r=-\frac{p}{3}\), we get \(p=\pm15\).
Exam Tip
जड़ें (r) और (4r) मानने पर \(4r^2=4\), इसलिए \(r=\pm1\)। योग \(5r=-\frac{p}{3}\) से \(p=\pm15\) मिलता है।
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