यदि \(qx^2-8x+12=0\) में मूलों का गुणनफल (4) है, तो (q) का मान क्या है?
If the product of roots of \(qx^2-8x+12=0\) is (4), what is the value of (q)?
Explanation opens after your attempt
Correct Answer
A. (3)
Concept
The product of roots is \(\frac{12}{q}=4\), so (q=3). Use \(\frac{c}{a}\) for the product of roots.
Why this answer is correct
The correct answer is A. (3). The product of roots is \(\frac{12}{q}=4\), so (q=3). Use \(\frac{c}{a}\) for the product of roots.
Exam Tip
मूलों का गुणनफल \(\frac{12}{q}=4\), इसलिए (q=3) है। गुणनफल के लिए \(\frac{c}{a}\) का प्रयोग करें।
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