यदि \(px^2+6x+9=0\) में मूलों का गुणनफल (3) है, तो (p) का मान क्या है?
If the product of roots of \(px^2+6x+9=0\) is (3), what is the value of (p)?
Explanation opens after your attempt
Correct Answer
A. (3)
Concept
The product of roots is \(\frac{9}{p}=3\), so (p=3). Use \(\frac{c}{a}\) for the product of roots.
Why this answer is correct
The correct answer is A. (3). The product of roots is \(\frac{9}{p}=3\), so (p=3). Use \(\frac{c}{a}\) for the product of roots.
Exam Tip
मूलों का गुणनफल \(\frac{9}{p}=3\), इसलिए (p=3) है। गुणनफल के लिए \(\frac{c}{a}\) का प्रयोग करें।
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