Hard Mathematics Polynomials Class 10 Level 24

यदि (p(x)=x-2+px+q) का ग्राफ ((-6,0)) और ((2,0)) पर (x)-अक्ष को काटता है तो (p) और (q) क्या होंगे?

If the graph of (p(x)=x-2+px+q) cuts the (x)-axis at ((-6,0)) and ((2,0)), what will (p) and (q) be?

Explanation opens after your attempt
Correct Answer

A. (p=4, q=-12)

Step 1

Concept

The zeroes are (-6) and (2), so the polynomial is ((x+6)(x-2)=x-2+4x-12). Tip: form factors from intersections.

Step 2

Why this answer is correct

The correct answer is A. (p=4, q=-12). The zeroes are (-6) and (2), so the polynomial is ((x+6)(x-2)=x-2+4x-12). Tip: form factors from intersections.

Step 3

Exam Tip

शून्यक (-6) और (2) हैं इसलिए बहुपद ((x+6)(x-2)=x-2+4x-12) है। टिप: कटान से गुणनखंड बनाएं।

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Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=x-2+px+q) का ग्राफ ((-6,0)) और ((2,0)) पर (x)-अक्ष को काटता है तो (p) और (q) क्या होंगे? / If the graph of (p(x)=x-2+px+q) cuts the (x)-axis at ((-6,0)) and ((2,0)), what will (p) and (q) be?

Correct Answer: A. (p=4, q=-12). Explanation: शून्यक (-6) और (2) हैं इसलिए बहुपद ((x+6)(x-2)=x-2+4x-12) है। टिप: कटान से गुणनखंड बनाएं। / The zeroes are (-6) and (2), so the polynomial is ((x+6)(x-2)=x-2+4x-12). Tip: form factors from intersections.

Which concept should I revise for this Mathematics MCQ?

The zeroes are (-6) and (2), so the polynomial is ((x+6)(x-2)=x-2+4x-12). Tip: form factors from intersections.

What exam hint can help solve this Mathematics question?

शून्यक (-6) और (2) हैं इसलिए बहुपद ((x+6)(x-2)=x-2+4x-12) है। टिप: कटान से गुणनखंड बनाएं।

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