यदि (p(x)=x-2+px+q) का ग्राफ ((-6,0)) और ((2,0)) पर (x)-अक्ष को काटता है तो (p) और (q) क्या होंगे?
If the graph of (p(x)=x-2+px+q) cuts the (x)-axis at ((-6,0)) and ((2,0)), what will (p) and (q) be?
Explanation opens after your attempt
A. (p=4, q=-12)
Concept
The zeroes are (-6) and (2), so the polynomial is ((x+6)(x-2)=x-2+4x-12). Tip: form factors from intersections.
Why this answer is correct
The correct answer is A. (p=4, q=-12). The zeroes are (-6) and (2), so the polynomial is ((x+6)(x-2)=x-2+4x-12). Tip: form factors from intersections.
Exam Tip
शून्यक (-6) और (2) हैं इसलिए बहुपद ((x+6)(x-2)=x-2+4x-12) है। टिप: कटान से गुणनखंड बनाएं।
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