यदि (x-2+(a-2)x+a=0) की जड़ों का अंतर (3) है, तो (a) का मान क्या है?
If the difference between the roots of (x-2+(a-2)x+a=0) is (3), what is the value of (a)?
Explanation opens after your attempt
Correct Answer
A. \(4+\sqrt{21}\) या \(4-\sqrt{21}\)\(4+\sqrt{21}\) or \(4-\sqrt{21}\)
Concept
Put (\(\alpha-\beta\)2=9) in (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta). This gives \(a^2-8a-5=0\), so \(a=4\pm\sqrt{21}\).
Why this answer is correct
The correct answer is A. \(4+\sqrt{21}\) या \(4-\sqrt{21}\) / \(4+\sqrt{21}\) or \(4-\sqrt{21}\). Put (\(\alpha-\beta\)2=9) in (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta). This gives \(a^2-8a-5=0\), so \(a=4\pm\sqrt{21}\).
Exam Tip
(\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta) में (\(\alpha-\beta\)2=9) रखें। इससे \(a^2-8a-5=0\) और \(a=4\pm\sqrt{21}\) मिलता है।
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