यदि \(3x^2-11x+p=0\) की जड़ों का अंतर \(\frac{5}{3}\) है, तो (p) का मान क्या है?
If the difference between the roots of \(3x^2-11x+p=0\) is \(\frac{5}{3}\), what is the value of (p)?
Explanation opens after your attempt
Correct Answer
A. (8)
Concept
Here \(\alpha+\beta=\frac{11}{3}\) and (\(\alpha-\beta\)2=\frac{25}{9}). Using (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta), we get \(\alpha\beta=\frac{8}{3}\), so (p=8).
Why this answer is correct
The correct answer is A. (8). Here \(\alpha+\beta=\frac{11}{3}\) and (\(\alpha-\beta\)2=\frac{25}{9}). Using (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta), we get \(\alpha\beta=\frac{8}{3}\), so (p=8).
Exam Tip
यहाँ \(\alpha+\beta=\frac{11}{3}\) और (\(\alpha-\beta\)2=\frac{25}{9}) है। सूत्र (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta) से \(\alpha\beta=\frac{8}{3}\), इसलिए (p=8)।
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